Saturday, January 25, 2020

Investigation of Subgrade Reaction Coefficient in Sandy Soil

Investigation of Subgrade Reaction Coefficient in Sandy Soil Numerical investigation of subgrade reaction coefficient in sandy soils Adel Asakereh1, Hassan Jamali2*, Masoud mossafa1 1 Civil Department, University of Hormozgan, Bandar Abbas, Iran 2Young Researchers and Elite Club, Sabzevar Branch, Islamic Azad University, Sabzevar, Abstract The soil-foundation interaction is one of the most important issues in geotechnical engineering relating to soil behavior against side loading. Winklers model is the first and simplest method for considering the soil-foundation interaction. Because to determine the coefficient of the subgrade reaction of the soil before designing structure is vitally important, so, experimental, analytical and numerical methods have been proposed. This research chose a ground characteristic that is in Bandar Abbas (Iran). Purpose is to compare the proposed experimental formulae for determining the coefficient of the subgrade reaction with its corresponding values resulting from the behavioral models. Finite element analysis was performed by Plaxis software and important parameters were proposed by the engineers. Results show increasing footing diameter leads to a decrease in the coefficient of the subgrade reaction due to increasing load area which results in increasing settlement. It is found that i ncreasing each of the strength parameters of the soil can be expected to have an effect on increasing the subgrade reaction, although this increase depends on footing diameter. Also in sand soils, the soil cohesion effects on the increase of the subgrade reaction coefficient more than the internal friction angle. Keywords: Elasticity coefficient, Mat foundation, Subgrade reaction coefficient, Bandar Abbas City, Finite element analysis Introduction The application of mat foundations has a long history. This type of foundation has shown a very good performance in transferring construction forces to the ground. Currently in most cases, engineers use a constant value for the subgrade reaction coefficient to analyze the mat flexible foundations. This constant is obtained from geotechnical experiments such as plate loading. Many researchers have studied soil subsidence and the subgrade reaction coefficient using plate loading test [1-9]. Nomenclatures B Diameter of footing (m) Minimum marginal dimension of footing(m) c Cohesion (kPa) d Plate thickness (m) Df Embedment depth of foundation(m) Soil elasticity modulus (kPa) EI Flexural rigidity of footing (kN.m2) EA Axial rigidity of footing (kN.m2) Height of ith layer (m) If , Is, Id Dimensionless coefficients ks Subgrade Reaction Coefficient (kN/m3) m Constant coefficients P Vertical pressure (kPa) Greek Symbols v Poisson ratio Vertical Displacement (m) Angle of friction (Degree) Unit weight (kN/m3) Dry unit weight (kN/m3) The application of a uniform reaction coefficient over all of the foundation means neglecting the conditions of a continuum for the soil and the effects of cut in the soil layers. One of the fundamental issues in designing and calculating the foundations is the problem of soil-foundation interaction. It is very important to study soil behavior against the external loads. Soil behavior depends on many factors such as moisture content, density, particle-forming mineral types, grain size, grain shape, grading curve, current state of the stress, stress history, pore pressure, saturation point, permeability rate, time, and temperature. In order to study the soil-foundation interaction, many researchers have tried to investigate soil behavior against the imposed loadings to find a model for it. The material model is a mathematical relation for describing the stress-strain behaviour of a small element of the environment. As previously mentioned, soil behavior depends on many factors it is extremely difficult to provide a model including the effects of all factors. Thus in solving the problems of soil-foundation interaction, some properties of the soil are usually excluded to provide a simpler model with fewer parameters. Since the soil at a macroscopic scale is considered as a continuum, the simplest possible state we consider the soil as a linear, homogenous and consistent elastic semi-space. In such a case, the soil will have two parameters Poisson coefficient and the elastic modulus. The first and simplest model for investigating the soil and foundation interaction is a model offered by Winkler in 1867 [10]. In this model, the deformation of any point of the soil ground is related to the point stress value and the effect of the stresses and the changes in other points are neglected. In this model, soil is replaced with a set of independent springs with a specific stiffness coefficient. Thus, only one single parameter is considered for the soil, that is, the subgrade reaction coefficient represented by ks. One of the most prominent properties of this model is its discontinuous behavior [9]. The subgrade modulus is not a fundamental soil property and its magnitude depends on many factors including the shape of the foundation, the stiffness of the foundation slab, the shape of the loading on the foundation, the depth of the loaded area below the ground surface, and the time. As such, it is not constant for a given type of soil, making the estimation of a single general value for design a challenging task [11]. Consequently, researchers have suggested several ways to determine this parameter and several formulae have been offered for determining ks. Many researchers have worked on the calculation of subgrade reaction coefficient. Ismail [12] studied the applications of the artificial neural networks (ANN) and the simple-multiple regression analysis to predict the deformation modulus and the coefficient of the subgrade reaction of the compacted soils from the compaction parameters (such as maximum dry density (MDD) optimum moisture content (OMC), field dry density (FDD), and field moisture content (FMC)). Ding [13] compared four typical methods for determining the coefficient of the subgrade reaction including the test method, Lis method, MIDAS method, and finite element method. He showed that the test method is the one preferred by the designers, that the tangential coefficient should be in a range of one to two-third of the normal coefficient. The internal force of subway structures can be obtained by the test method and modified by a correction factor that is 1.05. Barmenkova et al. [14] carried out calculations of plates on a n elastic basis with variable and constant coefficients of subgrade reaction. In this paper, the calculation of plates bending was carried out by the finite element method. The results were compared for different models of plates on an elastic basis. For a two-layer plate on an elastic basis, which had heterogeneity in the plan, the results of calculation took into account the increase of the height of the upper structure. Kobayashi et al. [15] calculated the subgrade reaction coefficient for a foundation soil in an open pier using an extended Kalman filter (EKF) based on measurements taken during in situ horizontal loading tests on a pile. The numerical results would provide useful information for the future design of open piers and their foundations. Liao [16] reviewed the limitations of various simple and complex methods available for estimating the coefficient of subgrade reaction k, and developed a new method using the results of the plane strain finite element analyses of a loaded beam or slab resting on the surface of a homogeneous elastic soil layer. Although many studies have been carried out on determining the subgrade reaction coefficient, the dependence on many parameters leads to further parametric studies. Experimental and theoretical formulas for determining ks are based on available data from limited sites with some assumptions, so it is possible for them not to have sufficient precision in all areas. Therefore, determining the subgrade reaction coefficient in specific areas such as Bandar Abbas city and assessment of the effective parameters on subgrade reaction coefficient is vital. Besides, the Increasing in footing width, increases effective depth. Therefore, determination of ks in footing with more width is more complex especially in layered soil, because ks obtained from plate load test is different from ks under real loading of structure. Thus investigation of the footing width and the strength parameters of the soil on ks is needed. Performing plate load tests with large diameters is expensive and difficult, thus the present study uses finite element software of Plaxis to investigate the effect of the aforementioned parameters. Parametric studies on subgrade reaction coefficient of sand soil in Bandar Abbas city are few, so this paper uses geotechnical data of a site in Bandar Abbas city (Iran) to determine subgrade reaction coefficient by using of theoretical, experimental relations and numerical methods. Besides, the effects of the strength parameters (c,) and B on subgrade reaction coefficient are investigated too. This study is carried out by using and verifying numerical methods and ensuring the accuracy of the software. Numerical analysis has been done by finite element method using Plaxis software [17]. Analytical methods of subgrades reaction coefficient In order to obtain ks, one can generally apply plate loading, consolidation, triaxial, and CBR tests and experimental and theoretic relations provided by researchers [18]. Among them, plate loading testing and the experimental method are considered the most common methods. In this paper, experimental and theoretic methods are considered. There are several relations including Vesic [19], Biot [20], and Bowles [6] as well as relations resulting from elastic theory from elasticity theory to determine subgrade reaction coefficient. Biot [20] solved the problem of an infinite beam on a linear elastic subgrade and provided Eq. (1) for subgrade reaction coefficient. (1) Vesic [19] developed Biots work [20] and suggested Eq. (2) for the relation between ks and elastic characteristic of soil: (2) He also showed the difference between Winkler method and continuum does not exceed 10 percent. Bowles [6] showed the numerical value of in ordinary condition may be approximated by 1, and in most cases subgrade reaction coefficient is obtained by Eq. (3): (3) Using elasticity theory is another way to approximate ks. By reformulating the elastic subsidence in rectangular foundation, we obtain the following [21]: (4) These values are determined based on tables in the elastic subsidence section of basic soil mechanic references. m is the coefficient which is equal to 1, 2 and 4 for corner, edge, and center, respectively. ks is calculated in corners assuming m = 1 from Eq. (4) and it is multiplied by 0.5 to obtain k edges or by 0.25 to obtain ks centers. According to the above discussion, it can be seen that there are several formulae to determine soil subgrade reaction coefficient. General and geotechnical properties of the soil The site of the residential- mercantile building is located to the west part of Bandar Abbas city in Iran (Fig. 1) with seven floors over the ground floor (parking lot). The depth of the foundation settlement is equal to the height of the foundation as 1 meter and no groundwater grade was observed until the end of the excavation depth. In order to identify the underground layers, five boreholes were excavated (three 15-meter boreholes and two 20-meter boreholes) using a rotary drilling machine. During soil boring, some samples were extracted for laboratory experiments. After completion of the field operation, the extracted samples were tested for grading, Atterberg limits, moisture content of the natural soil, and direct shear test. The studies on the layers of the site soil show the soil type in the foundation subgrade is mainly silty sand (SM) from the ground level down to the depth of 8 meters, and the soil type is bad-grained sand (SP) from the depth of 8 meters downwards. Fig. 1. Location of Bandar Abbas city. Considering the field and laboratory experiments in order to determine the scale of soil subsidence and the bearing capacity of the site soil, the required parameters were selected from the five excavated boreholes as shown in Table 1. The data of the samplings is available down to 20 meters deep. The soil type was given down to the depth of the foundation effect (around 30m). Moreover, the soil weight at the 20 to 30 m depth (layer 11) has considered as being constant. Table 1. Soil properties of the site No. of Layers Dep. (m) Soil Type SPT (Ncor.) à Ã¢â‚¬ ° (%) c (kPa) à Ã¢â‚¬   (ËÅ ¡) ÃŽÂ ³ (kN/m3) ÃŽÂ ³d(kN/m3) 1 0-2 SM 21 4.1 0 29 17 16.3 2 2-4 SM 17 16.6 0 29.1 18.6 16.23 3 4-6 SM 24 14.9 0 28.8 18.6 16.18 4 6-8 SM 33 15.2 0 30.4 18.9 16.4 5 8-10 SP 38 23.7 0 32.4 20.1 16.24 6 10-12 SP 39 18.1 0 31.2 19.4 16.42 7 12-14 SP 47 24.2 0 31.2 20.6 16.58 8 14-16 SP 50 19.8 0 30 20 16.69 9 16-18 SP 50 19.2 0 32 20 16.77 10 18-20 SP 50 18.8 0 32 20 16.83 11 20-30 SP 50 18.8 0 32 20 16.83 Equations (5) and (6) were used to determine the elasticity modulus of the soil [6]: (5) For unsaturated sands, and (6) For saturated sands. Thus, the elasticity modulus for each of the soil layers is calculated based on the above formulae and the results are shown in Table 2. Table 2. Elasticity modulus of the soil layers No. of Layers SPT (Ncor.) Es (kPa)-dry 1 21 18000 2 17 16000 3 24 19500 4 33 24000 5 38 26500 6 39 27000 7 47 31000 8 50 32500 9 50 32500 10 50 32500 11 50 32500 Numerical analysis procedure First, the results of Brian Anderson et al. [22] were analyzed with Plaxis to verify the software. Brian Anderson et al. [22] performed in situ testing and numerical investigation for predicting settlement of shallow foundations. Accordingly, a 1.8 m diameter concrete footing was statically load tested. Prior to construction, in situ standard penetration test (SPT), cone penetration testing (CPT), dilatometer (DMT), and pressuremeter (PMT) and laboratory tests were performed to determine engineering properties of the soil. A reinforced circular 1.8 m diameter 0.6 m thick concrete footing was constructed using a corrugated pipe coupler as a form. To overcome a thin hard layer surface crust, the footing was embedded 0.6 m into the ground. The groundwater table was at 1.7 m from the ground surface, as illustrated in Fig. 2. Static load was 222 kPa. Due to the symmetry, half of footing with the width of 0.5 B is modeled asymmetrically. Avoiding boundary effects, a 6.5ÃÆ'-5 m model was s elected. The model depth was taken as 6.5 m, that is approximately equal to 4B=6.8 m and the width of the model was taken as 5 m, that is approximately equal to 3B [23] . Results proved that the displacement did not reach the boundaries in the analysis. To investigate the mesh dependency, a number of trial analyses were conducted through the verification study. The model included 1971 nodes and 235 elements. The boundary lines were defined as the limited deformation in horizontal direction and free deformation in vertical direction, and limited deformations both in horizontal and vertical directions at the lower boundary as showed in Fig. 3. Trial analyses proved that with specified dimension and meshing, errors would be negligible. In order to do the modeling with finite element method, the 15-node triangular element was used according to Fig. 4. Table 3 presents the input parameters used for the FEM analyses. Figure 5 presents applied stress-settlement diagram obtained from Plaxis in this study and reference to a point located under plate. There was a negligible difference between two diagrams, so Plaxis was suitable for analysis. Fig. 2. Geometry and mesh of the verification model.  Ã‚  Ã‚   Fig. 3. Soil-footing profile of verification model [22]. Fig. 4. 15-node triangular element. Table 3. Soil properties used in verification according to [22]. Bottom(m) (kN/m3) (deg) E(Mpa) c(kPa) 1.64 18.9 31.4 14.5 0 2.5 17.3 30.1 12.5 0 3.17 15.7 28.6 10.50 0 6.5 14.2 27.1 8.5 0 Fig. 5. Applied stress-settlement diagram. After software verification, the model was developed for determining the subgrade reaction coefficient of Bandar Abbas city and parametric study. In the created model (which included 2011 nodes and 256 elements), the loading was uniform and, a rigid foundation was considered in all phases of analysis. Model depth should be greater than 4B and model width greater than 3B for different diameters. Since it was intended to study the effect of foundation diameter on determining the value of subgrade reaction coefficient, an asymmetric model was used in the software for soil modeling. The relevant parameters of the general properties (wet and dry specific weight) and the relevant parameters of the soil resistance (c,) for all soil layers were derived from Table 1. Considering the results of the experiments and researches and the reliability of the developed numerical model with the results, and considering the soil type of the site (sand soil), Mohr-Coulomb behavioral model for the soil wa s used in this research. Since in Mohr-Coulomb behavioral model the stress-strain relation is fulfilled directly by the soil elasticity coefficient, thus in entering the data of the soil elasticity coefficient as one of the input parameters, the data of Table 2 were used. The values of the dilation angle in all layers were assumed to be 0. Considering the properties of the building in this project and the scale of the imposed loading (dead and live load), the value of the imposed pressure on the soil was assumed to be 120 kN/m2 where the plate element (with the concrete foundation properties) was used to transfer this load to the modeled soil. Among the most important properties of the element, it could be referred to its flexural hardness (EI) and its axis hardness (EA). These two parameters can be used to obtain the plate thickness that is the representative of the foundation thickness in this case. Considering the constant thickness of the foundation by 1 meter in this research, different values would be obtained for EI and EA in different models according to the Eqs. (7) and (8) [24]. Since the modeling was done with asymmetric method, thus half of the diameter of the real foundation was modeled, and the modeling was done in direction of x-axis, three times more than the foundations diameter (3B), and in the direction of y-axis equal to the number of the layers mentioned in Table 1. Moreover, Table 4 shows the parameters needed for determining the plate input parameters into Plaxis software. d=  ½ deq (7) (8) Fig. 6. Geometry of the model. Table 4. Plate parameters EI (kNm2/m) EA (kN/m) E (kPa) Df(m) Var. Var. 2.5ÃÆ'-107 1 Results and discussion Seven models were developed for different values of foundation diameter (8, 10, 12, 14, 16, 18, and 20 m). Then, they were analyzed by finite element method using Plaxis. Because of axis plain strain in Plaxis, foundation is considered as a strip with B/2 of diameter and 1 m, orthogonal to the plane as shown in Fig. 6. Amount of vertical displacement in center and below of the foundation (sections are in center and 1 meter below the above subgrade of soil model) is obtained according to the load determined by the construction analysis (120 kN/m2). The soil subgrade reaction coefficient is calculated by Eq. (9) for any values of foundation diameter [25]: (9)

Friday, January 17, 2020

Corporate Strategies to Hedge Commodity Price Risks Applying

Table of contents List of abbreviationsIII List of figuresIII List of tablesIII 1Introduction1 1. 1Problem and objective1 1. 2Structure of this paper1 2Background Information2 2. 1Definitions of fundamental terms2 2. 2Commodity price risk in different firms2 3Explanation of derivatives3 3. 1Options3 3. 2Futures4 3. 3Forwards6 3. 4Swaps6 4Hedging strategies with derivatives7 4. 1Hedging with options7 4. 2Hedging with futures7 4. 3Hedging with forwards8 4. 4Hedging with swaps8 5Pros and cons of hedging strategies with derivatives8 5. 1Pros and cons of options9 5. Pros and cons of futures9 5. 3Pros and cons of forwards10 5. 4Pros and cons of swaps10 6Practical example of corporate commodity price risk hedging10 6. 1Introduction on firm's practical hedging strategy10 6. 2Analysis on this strategy11 7Summary12 Appendix13 Appendix 1: Amounts outstanding of over-the-counter (OTC) derivatives by risk category and instrument——in billions of US dollar13 Appendix 2: Derivatives fi nancial instruments traded on organized exchanges by instrument and location——in billions of US dollar14 Bibliography15 Internet Source16 List of abbreviations CHClearing HouseIMInitial Margin MBMargin Balance MM NMaintenance Margin No OTCOver The Count VM YVariation Margin Yes List of figures Figure 1: Structure of this paper2 Figure 2: P of each option position4 Figure 3: Flow chart of marking-to-market process5 Figure 4: P of each future position6 Figure 5: Hedging model on fuel oil of Air China11 List of tables Table 1: Summary for 4 option positions4 Table 2: Summary for future positions6 Table 3: Summary for 4 derivatives9 1Introduction 1. 1Problem and objective The risk of commodity price is a ferocious topic in corporate operation.Corporate profit is equal to total revenue minus total cost. For firms, because of the high volatility on commodity price, their inputs and outputs relating to commodity are unpredictable. As a consequence corporate profit will be imm ensely volatile, which will possibly lead the firm to go bankruptcy if no any preventive actions are taken. For example, producers of commodities probably need to assume unexpected losses, when the price of outputs goes down or the price of necessary raw materials goes up. The situations are similar to wholesale buyers, retailers, exporters and even governments.Volatility of commodities price has great impacts on corporate daily operation. The objective of this term paper is to introduce derivative hedging strategies for corporate managers to reduce or even eliminate future unpredictability, mainly from the perspectives of the role commodity price risks play, what the typical derivative instruments are, where and how to apply these different derivatives in terms of hedging principles thereof, and both advantages and disadvantages when applying each derivative in real business transactions. 1. Structure of this paper Firstly, this term paper highlights problems existing in real world . Secondly, it introduces advanced derivatives theory that can be applied to solve these problems. Thirdly, specific details on the theory will be presented, including explanation, application, as well as pros and cons of each derivative instrument. Then, an example is analyzed to show how companies apply derivatives to hedge commodity risks practically. Last is a summary of this term paper. Following figure shows the body of this paper. 2Background Information 2. Definitions of fundamental terms In financial markets derivative is a contract or security whose value is derived from the value of other more basic underlying variables . One of its most important functions is hedging. In corporate operation, hedging is to secure the companies against potential loss caused by variable risks that arise in international market, such as the commodity price risks. In this paper, commodity means any tangible goods or raw materials that may be sold or traded in the markets, such as energy, gold , or agricultural products. 2. Commodity price risk in different firms Volatility of commodities price influences firms’ daily operation significantly. Producers of commodities, such as farms, oil producers, mining companies, face price risk on output. Wholesalers and retailers, face price risk during the time period from buying from suppliers and selling to customers. Exporters, face the same price risk as well as currency exchange risk. And governments face price and yield risks generating from tax revenues that depend on firms’ operational conditions. 3Explanation of derivativesDerivatives are traded in exchange-traded markets and over-the-counter markets. (See recent derivatives transaction status in appendix 1 and appendix 2. ) Notably, exchange-traded derivatives are default risk free and liquid. However over-the-counter traded derivatives are the opposite. 3. 1Options An option is the contract that gives the buyer the right but not obligation to buy (call option ) or sell (put option) an underlying asset at a predetermined price (exercise price) for certain quantity during a fixed period of time (maturity).The buyer of the option pays a particular amount of money (option premium) to the seller to buy a right whereby he can decide whether or not to exercise this option, simultaneously the seller has the obligation to perform if the buyer exercises the option. European options only can be exercised on expiration day, and American options can be exercised at any time before maturity. The buyer of the call option is named long call, while the seller of the call option is named short call. Similarly, the buyer of the put option is named long put, while the seller of the put option is named short put.In commodity market, underlying of commodity option is a commodity, such as oil, wheat, or gold. Commodity options are both exchanges-traded and OTC traded. Following figure shows P of each option. Following table is the summary for these 4 option po sitions. Table 1: Summary for 4 option positions Market price expectationMaximum profitMaximum lossBreakeven point Long callupunlimitedoption premiumexercise price + option premium Short calldown or stableoption premiumunlimitedexercise price + option premium Long putdownexercise price – option premiumoption premiumexercise price – option premium Short putup or stableoption remiumexercise price – option premiumexercise price – option premium Source: author’s own. 3. 2Futures A future is a contract between two parties to buy or sell a specified amount of asset at a specified time period in the future for a certain price. Normally there are two types of futures, commodity futures whose underlying are commodities and financial futures whose underlying are financial assets. They are highly standardized, regulated, and traded in exchange markets with highly liquid and default risk free property. Because of the marking-to-market process, at maturity the settling price is the spot price at expiration date with profit gaining or loss paying from a margin account, which indirectly makes the effective bargain price equal to the predetermined price in the future contract. Notably, to ensure high liquidity of futures, marking-to-market process plays a significant role. The following figure shows the marking-to-market process. Generally there are two alternative ways at maturity to settle futures, either by cash or by actual delivery of underlying, which is clearly defined by futures exchange.Following figure and table show the details of a future. Table 2: Summary for future positions ?Maximum profitMaximum lossBreakeven point Long positionunlimitedexercise pricespot price + cost of carry Short positionexercise priceunlimitedspot price + cost of carry Source: author’s own. 3. 3Forwards A forward contract is a customized and over-the-counter agreement to buy or sell an asset at a specified time in the future for a specified price, where a long position has the obligation to buy and a short position has the obligation to sell. Compared with futures, no marking-to-market process are required.Counterparties can negotiate with each about the parameters of the contract. As a result, a firm who wants to make forward contract needs to find the counterparty by itself. 3. 4Swaps A swap is a customized and over-the-counter agreement to exchange a series of specified assets periodically in the future. Normally the counterparties of a swap contract are a large institution such as a bank and a company. Basically, we can view a swap as a complicated forward. Except currency swaps, counterparties just need to pay the differences between the cash flow they should exchange. Because swaps are bespoken as a result they are less liquid.There are commodity swaps, interest rate swaps and currency swaps. Interest rate swaps is an agreement of two counterparties to change fixed interest and floating interest on predefined nominal pr incipal in the future periodically. Commodity swaps normally vary tremendously among different markets. In a currency swap, counterparties change same value of different currencies in inception and termination, where the exchange rate of the tow currencies depends on the negotiation of counterparties. 4Hedging strategies with derivatives This chapter will focus on the principles of hedging strategies on commodities. . 1Hedging with options If a trader wants to procure a commodity with high volatile price, he can buy a commodity call option to hedge the price risk of going up. Similarly, if a company wants to sell a commodity product, it can buy a long put to hedge the price risk of going down. In practice, because investors want to bet more precisely on the future price of the underlying, and hedgers with long positions want to save option premiums, a few combinations of options come out, such as a long call and a short put with identical parameters except the different strike price . 4. 2Hedging with futuresWhen the objective of a commodity trader wants to neutralize the price risk as far as possible, usually he will choose to take a position on a future on commodity. A hedger who already owns a commodity asset or doesn‘t own right now but will at some future time expecting to sell it in the future without assuming any price risk, he can apple future hedging strategy to enter into a short position to become a short. Likewise, a hedger who has to buy a certain commodity asset in the future and wants to lock in spot price immediately, he can apply a future to enter into a long position to become a long. . 3Hedging with forwards The principles of hedging strategy with forwards are similar with futures'. Whether to use futures or forwards depends on different requirements. Generally, financial assets investors who need high liquidity prefer to choose futures, while commodity investors such as producers who need high customization prefer to choose forwards. 4 . 4Hedging with swaps When investors want to hedge risks of interest rates, currencies, or commodities, they can use swaps. In gold swaps, counterparties change fixed lease rate with variable lease rate.In swaps on base metals, counterparties change fixed metal price with average price of near dated metal future. In oil swaps, counterparties change fixed West Taxes Intermediate (WTI is a benchmark in oil price) price with average price of near dated WTI future. 5Pros and cons of hedging strategies with derivatives The following integrated summary of these derivatives depending on pervious analysis makes systematic comparisons. (The options here are exchanged-traded European options) Table 3: Summary for 4 derivatives SUMMERY OF DERIVATIVES FOR GENERAL TYPES OptionsFuturesForwardsSwapsTypes of contractstandardizedstandardizedcustomizedcustomized Settlementscash and deliverymost cash and few deliverydeliverydepends on individuals Trading marketExchange tradedExchange tradedOTCOTC Liqu idityhighhighlowlow Marketing-to-marginnorequirednono Time of settlementmaturitydailymaturityperiodically Initial investmentoption premiuminitial margin nodepends Default risk assumed byClearing houseclearinghouseBoth partiesBoth parties ProsDefault risk free & liquiditycustomization & no initial investment Consinitial investment & inflexibledefault risk for both party & illiquidity Source: author’s own. . 1Pros and cons of options The pros of options are obvious. Firstly, they have no risk to assume more loss than premium but have possibility to get unlimited potential profit. Secondly exchanged-traded options are highly liquid and OTC traded options are flexible. However, the cons of options are also explicit, such as the difficulty to decide when to enter into a long position.Because buying an option needs to pay option premium, if the spot price cannot go above (for a long call) or go below (for a long put) the breakeven point the hedger will suffer a loss, and depends on statistics the possibility of a long position to lose is about 66%. 5. 2Pros and cons of futures It definitely makes sense for most companies whose majors are in businesses but not professional in forecasting the price of commodities price volatility, which can make them pay more attention on their core competences instead of fearing about volatile price.Nonetheless, taking neutralized strategies make hedgers give up the possibility of both profit and loss. Moreover, instead of hedging risks by companies, shareholders can hedge themselves according to their preferences. Additionally, if other competitors of the same industry don’t apply hedging strategies, in fact, it is the hedging company itself that assumes risks, because competitive pressures are the same for other all competitors but different for the hedging company its own. 5. 3Pros and cons of forwards Basic pros and cons have been listed in the table in front of this chapter.Generally, compared to futures, the most explicit pro is that forwards are highly customized and therefore the con is that they are hardly liquid. 5. 4Pros and cons of swaps Basic pros and cons have been listed in the table in front of this chapter. Gernally, compared to futures and forwards the most precise pros is that both counterparties could reap benefits from a swap, such as in a currency swap where a firm with a low rate may get a cheaper loan as other firms with high rates, and the counterparty may get a payment as compensation.However the corresponding cons is that counterparty may need to pay commision to intermediary, because it is difficult to find an appropriate counterparty by itself. 6Practical example of corporate commodity price risk hedging 6. 1Introduction on firm's practical hedging strategy Air China is an airline company, whose cost of fuel oil occupies 44. 75% of total revenue in 2008. To hedge the fuel oil price risk, Air China bought a call option with strike K1, meanwhile sold a put option with st rike K2, where K1

Thursday, January 9, 2020

Project Management Institute A Project - 1539 Words

As stated by to the Project Management Institute, â€Å"A project is a temporary process which has a predetermined beginning and end according to the requirement, and therefore has a set of defined scope and resources. A project is unique as it is not a routine operation. It is rather a specific set of procedures and processes designed to accomplish the targeted goal† (Project Management institute, n.d.). A project is not a continuous or a permanent job which needs continuous work put into it. It is, therefore, different and separated from the daily operation of a company. Since a project is an undertaking of a company to attain some special assignments and tasks, it can be of different financial and operational sizes. Some projects can†¦show more content†¦A project team generally consists of people from different departments and backgrounds who are chosen by the project manager and/or senior management for the project’s successful completion. The proje ct manager, therefore, needs to be someone who has a variety of key soft skills and hard skills to lead the project with the help of the project team and complete it within the allocated time and budget. It is very important for a project manager to have a planned route to follow each step of the project. â€Å"By failing to prepare, you are preparing to fail† (Benjamin Franklin, n.d.). This saying by Benjamin Franklin should be the key mantra for every project manager. Lack of planning and preparation means a lack of planned route for the project team to follow. This is a perfect recipe for the failure of a project. Therefore, planning and preparing for every step of the project is very important. A planned project has a life cycle of its own. â€Å"Project life cycle is the series of phases that a project goes through from its initiation to its closure’ (Timothy J. Kloppenborg, 2014). Thus, a project has five phases – project initiation, project planning, project execution, project monitoring and control, and project closure. All of these five phases are very important for the successful completion of a project. Success of